Exercitium

Suma de cadenas
Publicado el 14 de febrero de 2024 por José A. Alonso

Índice

1. Enunciado

Definir la función

sumaCadenas :: String -> String -> String

tal que `sumaCadenas xs ys` es la cadena formada por el número que es la suma de los números enteros cuyas cadenas que lo representan son `xs` e `ys`; además, se supone que la cadena vacía representa al cero. Por ejemplo,

sumaCadenas "2"   "6"  == "8"
sumaCadenas "14"  "2"  == "16"
sumaCadenas "14"  "-5" == "9"
sumaCadenas "-14" "-5" == "-19"
sumaCadenas "5"   "-5" == "0"
sumaCadenas ""    "5"  == "5"
sumaCadenas "6"   ""   == "6"
sumaCadenas ""    ""   == "0"

2. Soluciones en Haskell

module Suma_de_cadenas where
import Test.Hspec (Spec, describe, hspec, it, shouldBe)

-- 1ª solución
-- ===========

sumaCadenas1 :: String -> String -> String
sumaCadenas1 xs ys =
  show (sum (map read (filter (not . null) [xs, ys])))

-- 2ª solución
-- ===========

sumaCadenas2 :: String -> String -> String
sumaCadenas2 =
  ((show . sum . map read . filter (not . null)) .) . (. return) . (:)

-- 3ª solución
-- ===========

sumaCadenas3 :: String -> String -> String
sumaCadenas3 "" "" = "0"
sumaCadenas3 "" ys = ys
sumaCadenas3 xs "" = xs
sumaCadenas3 xs ys = show (read xs + read ys)

-- 4ª solución
-- ===========

sumaCadenas4 :: String -> String -> String
sumaCadenas4 xs ys = show (numero xs + numero ys)

-- (numero xs) es el número entero representado por la cadena xs
-- suponiendo que la cadena vacía representa al cero.. Por ejemplo,
--    numero "12"   ==  12
--    numero "-12"  ==  -12
--    numero "0"    ==  0
--    numero ""     ==  0
numero :: String -> Int
numero "" = 0
numero xs = read xs

-- Verificación
-- ============

verifica :: IO ()
verifica = hspec spec

specG :: (String -> String -> String) -> Spec
specG sumaCadenas = do
  it "e1" $
    sumaCadenas "2"   "6"  `shouldBe` "8"
  it "e2" $
    sumaCadenas "14"  "2"  `shouldBe` "16"
  it "e3" $
    sumaCadenas "14"  "-5" `shouldBe` "9"
  it "e4" $
    sumaCadenas "-14" "-5" `shouldBe` "-19"
  it "e5" $
    sumaCadenas "5"   "-5" `shouldBe` "0"
  it "e6" $
    sumaCadenas ""    "5"  `shouldBe` "5"
  it "e7" $
    sumaCadenas "6"   ""   `shouldBe` "6"
  it "e8" $
    sumaCadenas ""    ""   `shouldBe` "0"

spec :: Spec
spec = do
  describe "def. 1" $ specG sumaCadenas1
  describe "def. 2" $ specG sumaCadenas2
  describe "def. 3" $ specG sumaCadenas3
  describe "def. 4" $ specG sumaCadenas4

-- La verificación es
--    λ> verifica
--
--    32 examples, 0 failures

3. Soluciones en Python

# 1ª solución
# ===========

def sumaCadenas1(xs: str, ys: str) -> str:
    return str(sum(map(int, filter(lambda x: x != '', [xs, ys]))))

# 2ª solución
# ===========

def sumaCadenas2(xs: str, ys: str) -> str:
    if xs == "" and ys == "":
        return "0"
    if xs == "":
        return ys
    if ys == "":
        return xs
    return str(int(xs) + int(ys))

# 3ª solución
# ===========

# numero(xs) es el número entero representado por la cadena xs
# suponiendo que la cadena vacía representa al cero.. Por ejemplo,
#    numero "12"   ==  12
#    numero "-12"  ==  -12
#    numero "0"    ==  0
#    numero ""     ==  0
def numero(s: str) -> int:
    if not s:
        return 0
    return int(s)

def sumaCadenas3(xs: str, ys: str) -> str:
    return str(numero(xs) + numero(ys))

# 4ª solución
# ===========

def sumaCadenas4(xs: str, ys: str) -> str:
    x = int(xs or "0")
    y = int(ys or "0")
    return str(x + y)

# Verificación
# ============

def test_sumaCadenas() -> None:
    for sumaCadenas in [sumaCadenas1, sumaCadenas2, sumaCadenas3,
                        sumaCadenas4]:
        assert sumaCadenas("2",   "6")  == "8"
        assert sumaCadenas("14",  "2")  == "16"
        assert sumaCadenas("14",  "-5") == "9"
        assert sumaCadenas("-14", "-5") == "-19"
        assert sumaCadenas("5",   "-5") == "0"
        assert sumaCadenas("",    "5")  == "5"
        assert sumaCadenas("6",   "")   == "6"
        assert sumaCadenas("",    "")   == "0"
    print("Verificado")

# La verificación es
#    >>> test_sumaCadenas()
#    Verificado

Exercitium

José A. Alonso Jiménez

Sevilla, 07 de abril del 2024

Licencia: Creative Commons.